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(F)=-3F^2-7F+6
We move all terms to the left:
(F)-(-3F^2-7F+6)=0
We get rid of parentheses
3F^2+7F+F-6=0
We add all the numbers together, and all the variables
3F^2+8F-6=0
a = 3; b = 8; c = -6;
Δ = b2-4ac
Δ = 82-4·3·(-6)
Δ = 136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{136}=\sqrt{4*34}=\sqrt{4}*\sqrt{34}=2\sqrt{34}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{34}}{2*3}=\frac{-8-2\sqrt{34}}{6} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{34}}{2*3}=\frac{-8+2\sqrt{34}}{6} $
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